find the area of a triangle whose sides are on the ratio 12:17:25 and perimeter is 540 cm
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heya !!!,
it's too easy ,
let the ratio of sides triangle be x .
then 1st side be 12x .
2nd ,,,,,,,,,,,,,,,17x.
and3rd,,,,,,,,,,,25।
perimeter of triangle =side +side +,side.
12x+17X+25x=540.
=)54x=540
=)x=10. ...........
now 1st side =12×10
=)120 .
2nd side =)17×10=170
3rd side =25×10=250
now by using herons formula ...
s=1/2(120+170+250)
s=540/2
s=270.
◆formula of herons.
=)√s(s-a)(s-b)(s-c)
=)√270(270-120)*(270-170)*(270-250)
=)√270(150)(100)(20)
=)√(2*5*3*3*3*2*3*5**5*2*2*5)
=)2*2*5*5*3*3
=)900cm^2Ans
hope it help you☺
@rajukumar☺☺☺
..
it's too easy ,
let the ratio of sides triangle be x .
then 1st side be 12x .
2nd ,,,,,,,,,,,,,,,17x.
and3rd,,,,,,,,,,,25।
perimeter of triangle =side +side +,side.
12x+17X+25x=540.
=)54x=540
=)x=10. ...........
now 1st side =12×10
=)120 .
2nd side =)17×10=170
3rd side =25×10=250
now by using herons formula ...
s=1/2(120+170+250)
s=540/2
s=270.
◆formula of herons.
=)√s(s-a)(s-b)(s-c)
=)√270(270-120)*(270-170)*(270-250)
=)√270(150)(100)(20)
=)√(2*5*3*3*3*2*3*5**5*2*2*5)
=)2*2*5*5*3*3
=)900cm^2Ans
hope it help you☺
@rajukumar☺☺☺
..
jorirul786:
ok thanks a lots for helping me
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