Question

Find the area of a triangle whose sides are respectively 150 cm,120cm and 200 cm.

Answer 1

using Heron's Formula = Area = √p(p−a)(p−b)(p−c)
p = a+b+c / 2
   = 120+150+200 / 2 =235
A = √235 (235-120) (235-150) (235-200)
   =  √235 (115) (85) (35)
   =  √235 x 342125
   =  8966.56985697 ( by rounding of )
A =  8966.57 cm²

Answer 2

$\huge{\underline{\underline{\red{♡Solution→}}}}$

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$\bold{\huge{\underline{\underline{\rm{ Given :}}}}}$

Sides -

a = 200 cm

a = 200 cm b = 150 cm

a = 200 cm b = 150 cm c = 120 cm

$\bold{\huge{\underline{\underline{\rm{ To\:Find :}}}}}$

Area of Triangle .

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The herons formula to find Area of Triangle is :

$area(a) = \sqrt{p(p - a)(p - b)(p - c)}$

Where P is half perimeter.

$p = \frac{a + b + c}{2}$

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$\purple{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

First find out the value of P.

$p = \frac{200+150+120}{2} \\ p = \frac{470}{2}$

$p = 235$

Now Area is ,

$a = \sqrt{235(235 - 200)(235- 150)(235 - 120)} \\ a = \sqrt{235 \times 35 \times 85 \times 115}$

$a = \sqrt{80,399,375}$

$\boxed{\red{a = 8,966.56986}}$

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