Question

find the area of a triangle whose two sides are 29m and 21m and perimeter is 70m​

Answer 1

Answer:

Triangle

Solve for area

A=210m²

a Side

29

m

b Base

21

m

P Perimeter

70

m

Answer 2

Answer:

A=210 sq m

Step-by-step explanation:

side a=29m

side b=21 m

side c = 70-(29+21)

c = 70-50

c = 20m

semi perimeter, s =(a+b+c)/2

s = 70/2 =35m

Area = √[s(s-a)(s-b)(s-c)]

A= √[35(35-29)(35-21)(35-20)]

A = √[35 ×6×14×15]

= √[44100]

A = 210sq. m.