Math, asked by basavarajh897100, 6 months ago

find the area of a triangle whose verticas are (1, -1) (-4, 6) and (-3, -5) ​

Answers

Answered by aayushsain9772
0

Answer:

í think (3,-3) (-12,2) and (-9,-15)

Answered by kartik2507
0

Step-by-step explanation:

Area = 1/2 [x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)]

 =  \frac{1}{2}  |1(6 - ( - 5) +  - 4( - 5 - ( - 1)) + ( - 3( - 1 - ( - 6)))|  \\  =  \frac{1}{2}  |(1 \times 11) + ( - 4 \times  - 4) + ( - 3 \times 5)|  \\  =  \frac{1}{2}  |11 + 16 - 15|  \\  =  \frac{1}{2}  |27 - 15|  \\  =  \frac{1}{2}  \times 12 \\  = 6

therefore the area of triangle is = 6 cm²

Hope you get your answer

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