Math, asked by HarmanSneh5175, 1 year ago

Find the area of a triangle whose vertices are (-7,-3) and (1,-7) and (3,0).

Answers

Answered by armaanarora880
5

Answer:

Step-by-step explanation:

Area of triangle  = 1/2 | x₁(y₂-y₃) + x₂(y₃-y₁) + x₃(y₁-y₂) |

                             = 1/2 | -7 (-7 -0) + 1(0+3) + 3(-3+7) |

                             = 1/2 | 49 + 3 + 12 |

                             = 1/2 |64|

                             = 1/2 * 64 = 32 unit²

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