Find the area of a triangle whose vertices are A( 2,3),B(4,5) and C (1,5)
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firstly calculate the distance then find the area using herons formulae
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Answer:
Step-by-step explanation:
i)
GIVEN:
Let A(2,3), B(−1,0) and C(2,−4) are the vertices of △ABC
Area of triangle=21[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]
Here (x1,y1)=(2,3)
(x2,y2)=(−1,0)
(x3,y3)=(2,−4)
=21[2(0+4)−1(−4−3)+2(3−0)]
=21[8+7+6]
=221 sq.unit
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