Math, asked by Mansi0509, 1 year ago

Find the area of a triangle whose vertices are given as (1, -1) , (-4 , 6 ) and (-3 , -5 ).​

Answers

Answered by jvsreddy1969
4

Answer:48

Step-by-step explanation:

Answered by Anonymous
6

Answer:

Area = 24

Step-by-step explanation:

Some step here is probably the formula that you use.  Feel free to ignore the steps before that one...

\displaystyle\text{Area}=\tfrac12\left|\begin{array}{ccc}1&1&1\\1&-4&-3\\-1&6&-5\end{array}\right|\\\\=\tfrac12\left|\begin{array}{ccc}0&0&1\\1-(-3)&-4-(-3)&-3\\-1-(-5)&6-(-5)&-5\end{array}\right|\\\\=\tfrac12\left|\begin{array}{cc}1-(-3)&-4-(-3)\\-1-(-5)&6-(-5)\end{array}\right|\\\\=\tfrac12\left|\begin{array}{cc}4&-1\\4&11\end{array}\right|\\\\=\tfrac12(4\times11-(-1)\times4)\\\\=\tfrac12(44+4)\\\\=\tfrac12\times 48\\\\=24

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