Question

Find the area of a triangle with base of 10 inches and altitude to the base of 16 inches.

80 in2
135 in2
160 in2

Answer 1

For the triangle ...

h = 16 in and the b= 10 in

we know that ....

Area of triangle = 1/2 × b × h

= 1/2 × 16 × 10

= 80 sq•inches

Answer 2

The area of triangle is 80 sq. in.

Step-by-step explanation:

Base of triangle = 10 inches

Altitude of triangle = 16 inches

Area of triangle = $\frac{1}{2} \times Base \times Height$

                         = $\frac{1}{2} \times 10 \times 16$

                         = $80 in^2$

Hence The area of triangle is 80 sq. in.

#Learn more:

The base area of a triangle is greater than twice the height 3cm. If the area of the triangle is 44cm² find the base and height of the triangle.

https://brainly.in/question/15505418