Find the area of a triangle with side 25,17,26cm. Also find the height of the triangle corresponding to the smallest side of the triangle
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Given :-
Sides of the triangle are 25cm, 17cm and 26cm.
Let the sides of the triangle be a, b and c respectively.
Semi-perimeter of the triangle = (25 + 17 + 26)/2
= 68/2
= 34cm
Using heron's formula,
= √[s(s - a)(s - b)(s - c)]
= √[34(34 - 25)(34 - 17)(34 - 26)]
= √(34 × 9 × 17 × 8)
= √(2 × 17 × 3 × 3 × 17 × 2 × 2 × 2)
= √(2 × 2 × 2 × 2 × 3 × 3 × 17 × 17)
= 2 × 2 × 3 × 17
= 204cm²
The area of the triangle is 204cm²
Now, here the shortest side is 17cm.
We also know that,
1/2 × b × h = area of a triangle
➡ 1/2 × 17 × h = 204cm²
➡ h = (204 × 2)/17
➡ h = 12 × 2
➡ h = 24cm
Hence, the of the triangle corresponding to it's smallest side is 24cm.
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