Question

FIND THE AREA OF A TRIANGLE WITH SIDES 28M, 15M AND 41M.
PLEASE TELL ME THE ANSWER PLEASE FAST​

Answer 1

first give correct information

Answer 2

To find:

THE AREA OF A TRIANGLE WITH SIDES 28M, 15M AND 41M.

Calculation:

Let semi-perimeter be s ;

$s = \dfrac{28 + 15 + 41}{2} = \dfrac{84}{2} = 42 \: m$

Now , applying Heron's formula:

$area = \sqrt{s(s - 28)(s - 15)(s - 41)}$

$= > area = \sqrt{42(42- 28)(42 - 15)(42 - 41)}$

$= > area = \sqrt{42 \times 14 \times 27 \times 1}$

$= > area = \sqrt{14 \times 3 \times 14 \times {3}^{3} }$

$= > area = \sqrt{ {14}^{2} \times {3}^{4} }$

$= > area = 14 \times {3}^{2}$

$= > area = 14 \times 9$

$= > area = 126 \: {m}^{2}$

So, final answer is:

$\boxed{ \bf{ area = 126 \: {m}^{2} }}$