Question

Find the area of a triangle with vertices (a,b+c),(b,c+a),and (c,a+b).

Answer 1

answer=1/2(-2a^2+b^2-ab)

Answer 2

$area \: of \: triangle \: is \: \\ \frac{a(c + a - a - b) + b(a + b - b - c) + c(b + c - c - a)}{2} \\ = \frac{ac - ab + ab - bc + bc - ac}{2} \\ = 0$