find the area of a triangular field of sides 18m 24m and 30m. Also find the altitude corresponding to the shortest sides.
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HEY !!! HERE IS YOUR ANSWER 》》
for the area :
S = (a+b+c) / 2 = (18+24+30) / 2 = 72 / 2 = 36
area + under root S (S-a) (S-b) (S-c) = 36 (36-18) (36-24) (36-30)
= under root 36 * 18 *12 *6 = under root 6*6*6*3*6*2*2*3 = under root 64 * 32 * 22
when we open the root the number becomes,
62 * 3 *2 = 36 * 6 = 216
then the area of the triangle is 216 cm2
now for finding the altitude :
we know that we have another method of finmding the area of a triangle = 1/2 * base * height
so by putting it
1/2 * 30 * h = 216
15 * h = 216
h = 216/15 = 14.4 cm
altitude = 14.4 cm
HOPE IT HELPS ^_^
for the area :
S = (a+b+c) / 2 = (18+24+30) / 2 = 72 / 2 = 36
area + under root S (S-a) (S-b) (S-c) = 36 (36-18) (36-24) (36-30)
= under root 36 * 18 *12 *6 = under root 6*6*6*3*6*2*2*3 = under root 64 * 32 * 22
when we open the root the number becomes,
62 * 3 *2 = 36 * 6 = 216
then the area of the triangle is 216 cm2
now for finding the altitude :
we know that we have another method of finmding the area of a triangle = 1/2 * base * height
so by putting it
1/2 * 30 * h = 216
15 * h = 216
h = 216/15 = 14.4 cm
altitude = 14.4 cm
HOPE IT HELPS ^_^
Shrishty15012003:
sir do me favor plz solve it on ur notebook plz tomorrow is my exam,humble request
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