plz explain this sum
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angle ADB=70°
angle BAC=30°
Also,ABCD is a cyclic quadrilateral
So,angle ADC+angle ABC= 180°(opposite angles of a cyclic quadrilateral are supplementary)
So,angle ABC+ 70° = 180°
angle ABC=180°-70°
=110°
THANKS!
angle BAC=30°
Also,ABCD is a cyclic quadrilateral
So,angle ADC+angle ABC= 180°(opposite angles of a cyclic quadrilateral are supplementary)
So,angle ABC+ 70° = 180°
angle ABC=180°-70°
=110°
THANKS!
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