Question

Find the area of a triangular field whose sides are 50 m, 45 m, and 35 m. Also find the

length of the altitude of the shortest side of the triangle.​

Answer 1

The corresponding of the triangle is 18m,24m30m

so, A=18m,B=24m,C=30m

By using herons formula we

S=

2

a+b+c

S=

2

18+24+30

=

2

72

=36

AREA=

S(S−A)(S−B)(S−C)

AREA=

36(36−18)(36−24)(36−30)

AREA=

36(18)(12)(6)

AREA=

46656

AREA=216m

2

Let altitude is Hm

AREA of triangle is also written as=

2

1

×b×h

216=

2

1

×18×h

h=

18

216×2

=24m

Answer 2

this is 764.85 m^2 answer