Question

Find the area of a triangular field whose sides are 78m, 50m, and 112m

Answer 1

Answer:

The  Area of triangle is 1680 m² .

Step-by-step explanation:

Given as :

The side of triangle are

Let AB = a = 78 m

     BC = b = 50 m

     CA = c = 112 m

Applying Heron's formula

S =  $\dfrac{a+b+c}{2}$

Or, S = $\dfrac{78+50+112}{2}$

Or, S = $\dfrac{240}{2}$ = 120.

Area of triangle = $\sqrt{S(S - a) (s-b) (s-c)}$

Or, Area of triangle = $\sqrt{120 (120 - 78) ( 120 - 50 ) ( 120 - 112 )}$

Or, Area of triangle = $\sqrt{120\times 42\times 70\times 8}$

Or,  Area of triangle = $\sqrt{2822400}$

∴   Area of triangle = 1680   m²

Hence, The  Area of triangle is 1680 m² . Answer