find the area of a triangular field whose sides are 91m ,98m and 105m in lenght find the height corresponding to the longest side
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let a = 91 b = 98. c. = 105
let the semiperimeter = a + b + c /2
= 91 + 98 + 105/2
s = 147
s - a = 147 - 91 = 56
s - b = 147 - 98 = 49
s- c. = 147 - 105 = 42
therefore the area of traingle using herone formulae =underroot 147 × 56 × 49 × 42
= 4116 m^2
hope this is helpful
let the semiperimeter = a + b + c /2
= 91 + 98 + 105/2
s = 147
s - a = 147 - 91 = 56
s - b = 147 - 98 = 49
s- c. = 147 - 105 = 42
therefore the area of traingle using herone formulae =underroot 147 × 56 × 49 × 42
= 4116 m^2
hope this is helpful
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