Question

Find the area of AABC in which AB = AC = 4 cm and
A = 90°.
night angled triangle of hypotenus​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

area=1/2*AB*AC=1/2*4*4

=8 cm²

Step-by-step explanation:

AB=AC=4 cm

∠A=90° so BC is hypotenuse

and area=1/2*AB*AC=1/2*4*4

=8 cm²