find the area of ∆abc given that .∆abc=∆cab=45°,ac=8cm
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yaa
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triangle ABC is a right angle isoceles triangle
right angled at ACB
and as the two angles are given equal then it will be equal to BC
the area of triangle ABC will be equal to half into base into height
then area of triangle ABC is equal to half into 8 into 8
area of triangle ABC is equal to 32 cm^2
right angled at ACB
and as the two angles are given equal then it will be equal to BC
the area of triangle ABC will be equal to half into base into height
then area of triangle ABC is equal to half into 8 into 8
area of triangle ABC is equal to 32 cm^2
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please brainliest my answer
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