find the area of ∆abc given that.bc=5cm,ca=7cm,and∆bca=90°
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3
area=1/2×base×height
area=1/2×5×7
area=17.5cm^2
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2
as base of triangle is 7 cm and height is 5 cm ....so we have to put them in formula .......
Area of triangle = 1/2 * b * h
= 1/2 * 7 * 5
= 35/2
= 17.5 cm^2
Area of triangle = 1/2 * b * h
= 1/2 * 7 * 5
= 35/2
= 17.5 cm^2
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