Question

Find the area of ∆abc given that is angle abc = angle cab =45°,ac = 8cm

Answer 1

given angleabc=anglecab=45°
ac=8cm
therefore anglebca=90°
then that triangle is an isosceles right angled triangle
therefore two sides are equal they are ac and bc since if two angled are equal then there opposite sides also equal
then area =1/2by
=1/2*8*8
=4*8
=32squarecm