Question

Find the area of ABC with A(1, -4) and midpoints of sides through A
being (2, -1) and (0, -1).

Answer 1

Step-by-step explanation:

let A =(1,-4)

b=(2,-1)

c=(0,-1)

area of triangle abc=

1/2[1(-1-(-1)+2(-1-(-4)+.0(-4-(-1)]=1/2(2+10+0)=

1/2+12 =6sq units

area of ABC is 6sq units