Find the area of aluminium sheet required to maje a closed box 4m long 2m wide 1m height
Answers
Answered by
6
Answer:
given,
long is 4m
wide is 2m
height is 1m
now,
area of aluminium sheet required = 2 [ ( l × b ) + ( l× h ) + ( b× h )
=2 [8+2+4]
=2 [14]
=28m
Answered by
7
Answer:
28 m^2
Step-by-step explanation:
l = 4m
b = 2m
h = 1m
Area of aluminium sheet required = 2(lb + bh + hl)
= 2 (8 + 2 + 4)
= 2 (14)
= 28 m^2
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