Question

find the area of an equilateral
triangle each of whose side is10cm​

Answer 1

Area of equilateral Δ = $\frac{ \sqrt{3} }{4} {side}^{2}$

= $\frac{ \sqrt{3} }{4} {10}^{2}$

= $\frac{ \sqrt{3} }{4} \times 100$

= $25 \sqrt{3} \: {cm}^{2}$

Answer 2

Answer:

area of equilateral triangle= √3/4×a^2

√3/4×10^2 =√3/4×100

= 1.73×100/4. (√3=1.73)

173\4= 43•25cm^2

or 25√3cm^2