Find the area of an equilateral triangle inscribed in a circle of radius 32cm
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Let the triangle be ABC inscribed in the circle where all the medians (AD, BE and CF) intersect at O
Area of the circle = pi x r2 = 3.14 x 32 x 32 = 3215.36 cm2
clearly, AO/OD = 2:1
=> 32/OD = 2
+> OD = 16
Hence, AD = AO + OD = 16 + 32 = 48
Hence, root (3) x a /2 = 48
=> a = 32 x root (3)
Hence, area of the triangle = root (3) x a2 / 4 = 135.53 cm2
Hence, area of the region not included in the triangle = 3215.36 - 135.53 = 3079.83 cm2
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