Find the area of an equilateral triangle (regular 3-gon) with the given measurement. 9-inch perimeter
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Answered by
1
find using the pythagorean theorem or the 30 60 90 triangle features
1.5^2+h^2=3^2
h^2=6.74
h=2.598
which we could have gotten from sqrt(3)*(1.5) a relationship of 30 60 90 triangles
so the height is sqrt(3)*1.5
and the base is 1.5
a=.5*b*h
a=.5*1.5^2*sqrt(3)
or a=.5*1.5*2.598
a=1.95
1.5^2+h^2=3^2
h^2=6.74
h=2.598
which we could have gotten from sqrt(3)*(1.5) a relationship of 30 60 90 triangles
so the height is sqrt(3)*1.5
and the base is 1.5
a=.5*b*h
a=.5*1.5^2*sqrt(3)
or a=.5*1.5*2.598
a=1.95
Answered by
6
as the triangle is equilateral it will have same side lengths.
therefore each side is equal to 3
therefore by using the formula of area √3/4×sidesquare
the area is 9√3/4
therefore each side is equal to 3
therefore by using the formula of area √3/4×sidesquare
the area is 9√3/4
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