please send me correct solution Class 7 ch 5 Lines and angles Ex 5. 2 mathematics Manjeet Singh Q no. 1 and 2 I know I am write answers
Answers
Step-by-step explanation:
Q1. Since n is a transversal which intersects l and m.
Also l is parallel to m.
(i) m∠3 = 70° given
m∠5 = m∠3 (alternate interior angle)
hence m∠5 = 70°
(ii) Since n is a transversal which intersects l and m.
m∠4 + m∠5 =180° (angle on the same side of the transversal)
m∠4 = 180 - 60
m∠4 = 120°
(iii) m∠2 + m3 = 180° => m∠3 = 180° - m∠2 -------------- 1.
and m∠3 + m∠6 = 180° (angle on the same side of the transversal) ----------2.
From 1 and 2
180° - m∠2 + m∠6 = 180°
=> -m∠2 + m∠6 =0
=> m∠2 = m∠6
=> m∠2 = 135°
Q2. given m∠1 = 60°, m∠2 = 120°. m∠4 = 120°
∠3= ∠1 (vertically opposite angle)
∠3 = 60° --------(i)
∠3 + ∠6 = 180° (angles on the same side of the transversal)
∠6 = 180° - ∠3
= 180° - 60° = 120°
∠6 = 120° ----------(ii)
∠4 + ∠5 = 180° (angles on the same side of the transversal)
∠5 = 180° - ∠4
= 180° - 120° = 60°
∠5 = 60° ----------(ii)
∠7 = ∠5 (vertically opposite angle)
∠7 = 60°
∠8 = ∠6 (vertically opposite angle)
∠8 = 120°
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