Find the area of an equilateral triangle the length of whose one side is ‘a’
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Given :
⠀⠀⠀⠀⠀⠀⠀⠀ • Length of one side of an equilateral triangle is 'a'.
Construction :
⠀⠀⠀⠀⠀⠀⠀⠀• Draw a perpendicular bisector to the base of height 'h'.(see in fig. in attachment)
Now,
Area of Triangle = ½ × base × height
Here, base = a, and height = h
Now, apply Pythagoras Theorem in the triangle.
a² = h² + (a/2)²
⇒ h² = a² – (a²/4)
⇒ h² = (3a²)/4
Or, h = ½(√3a)
Now, put the value of “h” in the area of the triangle equation.
Area of Triangle = ½ × base × height
⇒ A = ½ × a × ½(√3a)
⇒ A = (√3/4)a²
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Answer:
√3 a^2 / 4
Step-by-step explanation:
Given,
side = a units
Area of an equilateral triangle = √3 a^2 / 4
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