Find the area of an equilateral triangle with side 2√3
cm.
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3
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Height of the cylindrical part =13cm
Radius of cone , cylinder and hemi sphere=5cm
r=5cm for hemisphere cylinder and cone.
Height of cone h=30−5−13=12
The area of canvas required=Surface area of hemishphere,cylinder and cone parts of tent
A=2πr
2+2πrH+πr( h2 +r2 )A=2π×5×5+2π×5×13+π×5( 5 2 +122 ) A=770cm2
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√3/4*(side)^2
=√3/4*(2√3)^2
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=√3/4*(2√3)^2
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