FIND THE AREA OF AN EQUILATERAL TRIANGLE WITH SIDE IS 8 CM. FIND THE AREA OF THE FIGURE FORMED BY PLACING ANOTHER EQUILATERAL TRIANGLE OF THE SAME SIZE ALONG ONE OF ITS SIDES. WHAT IS THIS FIGURE CALLED? FIND THE LENGTH OF ITS DIAGONALS?
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ar. of equilateral triangle =√3/4*a sq.
the figure formed is rhombus
thank you
smishra01:
thanks shreya
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Area of an eqilayeral triangle is v√3×a^2/4.
a=8
√3×8×8/4 = 163 cm²
The new figure is a parallelogram
Length of diagonal is 8
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