Find the area of an inqulateral tringle inscribed in the circle x²+y²-6x+2y-15=0
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radius =root (9+1+15)=5 unit
now use cosine formula
cos120={(5)^2+(5)^2-(x)^2}/2.5.5
-1/2=(50-x^2)/50
-25=50-x^2
x=5root3
here x is side length of triangle
area of triangle=root3/4 (side length)^2
=root3/4 (5root3)^2
=75root3/4 square unit.
now use cosine formula
cos120={(5)^2+(5)^2-(x)^2}/2.5.5
-1/2=(50-x^2)/50
-25=50-x^2
x=5root3
here x is side length of triangle
area of triangle=root3/4 (side length)^2
=root3/4 (5root3)^2
=75root3/4 square unit.
abhi178:
please mark as brainliest
ok
Kya yeh ans write h
yes I think this is right answer
thank you
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