Find the area of an isosceles right - angled triangle if one of the equal sides is 20 cm long.
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Answer:
area of isosceles right triangle
\begin{gathered} = \frac{1}{2} \times {side}^{2} \\ = \frac{1}{2} \times {20}^{2} \\ = \frac{1}{2} \times 20 \times 20 \\ = 10 \times 20 \\ = 200 {cm}^{2} \\ \end{gathered}
=
2
1
×side
2
=
2
1
×20
2
=
2
1
×20×20
=10×20
=200cm
2
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