Find the area of an isosceles right angled triangle in which one of the equal sides is 20cm.
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Answered by
2
area = 1/2 hx b
area = 20 x20 /2
area = 200 cm^2
area = 20 x20 /2
area = 200 cm^2
Answered by
0
Hypotenuse=20 cm
According to Pythagoras theorem,
Hypotenuse ²=side²+side²
Let hypotenuse=a
Base=b
Height=c
In an isosceles right angled triangle,
The other two sides are equal.
So,base=height=b
Apply Pythagoras theorem,
a²=b²+b²
a²=2b²
b=√(a²/2)
b=√(20²/2)
b=20/√2
Area of isosceles right angled triangle=1/2×b×h
=1/2×20/√2×20/√2
=1/2×400/2
=400/4
=100 cm²
Hope it helps
According to Pythagoras theorem,
Hypotenuse ²=side²+side²
Let hypotenuse=a
Base=b
Height=c
In an isosceles right angled triangle,
The other two sides are equal.
So,base=height=b
Apply Pythagoras theorem,
a²=b²+b²
a²=2b²
b=√(a²/2)
b=√(20²/2)
b=20/√2
Area of isosceles right angled triangle=1/2×b×h
=1/2×20/√2×20/√2
=1/2×400/2
=400/4
=100 cm²
Hope it helps
mysticd:
it is wrong
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