Math, asked by mysticd, 1 year ago

Find the area of an isosceles right angled triangle in which one of the equal sides is 20cm.

Answers

Answered by AionAbhishek
2
area = 1/2 hx b
area = 20 x20 /2
area = 200 cm^2
Answered by snehitha2
0
Hypotenuse=20 cm
According to Pythagoras theorem,
Hypotenuse ²=side²+side²
Let hypotenuse=a
Base=b
Height=c
In an isosceles right angled triangle,
The other two sides are equal.
So,base=height=b

Apply Pythagoras theorem,
a²=b²+b²
a²=2b²
b=√(a²/2)
b=√(20²/2)
b=20/√2

Area of isosceles right angled triangle=1/2×b×h
=1/2×20/√2×20/√2
=1/2×400/2
=400/4
=100 cm²

Hope it helps

mysticd: it is wrong
mysticd: it is isosceles right angled triangle.
mysticd: two equal sides are those which make right angle
mysticd: a=b =20 cm
mysticd: A=ab/2 =(20*20)/2=200 cm^2
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