Question

Find the area of an isosceles right angled triangle of equal sides 15 cm each.

Answer 1

GIVEN:

• Side of an isosceles equilateral triangle = 15 cm

TO FIND:

• What is the area of triangle ?

SOLUTION:

We have given that all sides of an isosceles equilateral triangle are equal.

• Side = 15 cm

We know that the formula for finding the area of an isosceles equilateral triangle is:-

$\large{\boxed{\bf{\star \: AREA = \dfrac{1}{2} \times base \times height \: \star}}}$

• BASE = 15 cm
• HEIGHT = 15 cm

According to question:-

On putting the given values in the formula, we get

$\sf{\longmapsto AREA = \dfrac{1}{2} \times 15 \times 15}$

$\sf{\longmapsto AREA = \dfrac{1}{2} \times 225}$

$\sf{\longmapsto AREA = \cancel\dfrac{225}{2}}$

$\bf{\longmapsto AREA = 112.5 \: cm^2}$

❝ Hence, the area of an isosceles equilateral triangle is 112.5 cm² ❞

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Answer 2

$\huge\underline\bold\red{Answer}$

Given :-

• Side of an isosceles right triangle is 15 cm.

To Find :-

• Area of the isosceles triangle.

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We know that area of an isosceles right triangle is

1/2 × base × height

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As it is given that all sides are equal

Then,

1/2 × 15 × 15

=> 225/2

=> 112.5 cm²

Hence, the area of the triangle is 112.5 cm²

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