Math, asked by lardizabaldaniela136, 4 months ago

Find the area of an isosceles trapezoid if the measure of one angle is 135o and the lengths of the bases are 10 and 18.

Answers

Answered by spratyusha20

So, if you position the trapezoid with the long base on the bottom, you have to draw an altitude from one of the top vertices down. This creates a 30-60-90 triangle. The side of that triangle that is part of the long base equals half the difference between the bases, or (17-12)/2 = 2.5.

2.5 is the short leg of the triangle, and the altitude drawn is the long leg. The altitude is

h = 2.5√3

So, the area of a trapezoid is (1/2)(b1+b2)h

=(1/2)(12+17)(2.5√3)

=36.25*√3

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