Question

Find the area of an isosceles triangle, the measure of one of its equal sides being a and the third side being b.

Answer 1

Step-by-step explanation:

area of traingle=1/2×base×height

for height we have to find by Pythagoras theorem

therefore height^2=a^2+(b/2)^2

a^2+b^2/4

√a^2+b^2/4

1/2√4a^2+b^2...(1)

now area,

1/2×b×1/2√4a^2+b^2

1/4×b×√4a^2+b^2

hope it helps.....