Find the area of an isosceles triangle , the ratio of whose equal side to its base is 3:2 and the perimeter is 32 cm.
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The perimeter of isosceles triangle = 32cm
p of isosceles triangle = 2 * equal side + base
let length of equal side be 3x and base be 2x
then
2 * 3x + 2x = 32 cm
6x + 2x = 32cm
8x = 32 cm
x= 4 cm
length of equal side = 3*4= 12cm
length of base = 2*4=8cm
area of isosceles triangle=b*1/4*√4a2-b2
= 8*1/4√4*144-64
=2√512
=2*22.62
= 45.25cm2
p of isosceles triangle = 2 * equal side + base
let length of equal side be 3x and base be 2x
then
2 * 3x + 2x = 32 cm
6x + 2x = 32cm
8x = 32 cm
x= 4 cm
length of equal side = 3*4= 12cm
length of base = 2*4=8cm
area of isosceles triangle=b*1/4*√4a2-b2
= 8*1/4√4*144-64
=2√512
=2*22.62
= 45.25cm2
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