Math, asked by Sruthi49, 8 months ago

Find the area of an isosceles triangle whose base is 16 cm and length of each of the equal sides is 10 cm

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Answered by Anonymous
4

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Answered by T546
0

Answer: 48 cm²

Step-by-step explanation: Base=16cm, Each of equal sides=10cm.

Formula for area of isosceles triangle=1/2*base*√(equal side)²-(base/2)².

Using this formula,

Area of triangle=1/2*16*√10²-(16/2)² cm²

=1/2*16*√100-64 cm²

=8*√36 cm²

=8*6 cm²

=48 cm² (Answer)

Hope this helps.

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