Find the area of an isosceles triangle whose equal sides measure 10 cm each and
the third side is 12 cm.
Answers
Answered by
9
Answer:
Area of triangle=1/2*Base*Height
=1/2*10*12
=5*12
=60cm^2
Step-by-step explanation:
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Answered by
8
area of triangle=1/2.b.h
=1/2.12.8{h=√100-64}
= 48m^2
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