Question

find the area of an isosceles triangle whose one of the equal sides measures 10cm and the third side is 8cm

Answer 1

Answer:

Step-by-step explanation:

Given sides of triangle a = 10, b = 10 and c = 8

Semi perimeter of the triangle, s = (a + b + c)/2

s = 14

Using Heron's formula to find the area of the triangle,

A = √s(s-a)(s-b)(s-c)

Hence, Area of the given triangle ca be calculated as

⇒A = √14(14-10)(14-10)(14-8)

⇒A = √14*4*4*6

⇒A = √1344 = 8√21 cm²

Hence, Area of the triangle is 8√21 cm²

Hope, it helped !