Find the area of an isosceles triangle whose perimeter is 32cm and its base is 12cm
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Answer:
48(cm)2
Step-by-step explanation:
Area of a triangle=1/2*base*height
The two equal sides of the isosceles triangle= (32-12)/2=20/2=10
height=vertical line from apex to the base=√(10^2-6^2)=√(100-36)=√64=8
Area=1/2*12*8=48 cm^2
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