Math, asked by annonymous27, 4 months ago

Find the area of an Isosceles Triangle Whose Perimeter is 72cm and the base is 20cm.

Answers

Answered by kritika12322
0

Answer:

s = a+b+c/2

s=72/2

s=36cm

Area =

  = \sqrt{36(3 6 - 26)(36 - 26)(36 - 20)}

 \sqrt{36 \times 10 \times 10 \times 16}

 \sqrt{2 \times 2 \times 3 \times 3 \times 10 \times 10 \times 4 \times 4}

2 \times 3 \times 10 \times 4

 = 240cm {}^{2}

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