Question

Find the area of atrapezium whose parellel side are 14cm and 10cm and whose height is 6cm

Answer 1

$\red{\textbf{Answer :- 72 sq cm}}$

Step-by-step explanation:

$\red{\textbf{Given:-}}$

$\textsf{a = 14cm}$

$\textsf{b= 10cm}$

$\textsf{height = 6cm}$

$\red{\textbf{To find :-}}$

$\textsf{Area of trapezium.}$

$\Large\textsf{So ,}$

$\textsf{Area of trapezium =}$

$\textsf{(1/2) x h x (a + b)}$

$\textsf{Hence ,area of trapezium =}$

$\textsf{ (1/2) x 6 x (14 + 10)}$

$\textsf{= 3 x 24}$

$\textsf{72 sq cm}$

$\Large\textsf{Thus, Area of trapezium = }$

$\LARGE\textsf{72 sq cm}$

$\red{\textbf{More information :-}}$

• Trapezium, is a flat closed shape having 4 straight sides, with one pair of parallel sides.

• Area: ½ x (sum of the lengths of the parallel sides) x perpendicular distance between parallel sides

• Perimeter: sum of lengths of sides of trapezoid