Question

x and. B are the zeroes of quadratic
Polynomial f (x) 6x²+x-2, find the value
of
ole
+ 8​

Answer 1

Answer:

6x²+ x- 2 = 0

a = 6 , b= 1 ,c = -2

If alpa and beta are the zeroes of the polynomial then

alpa + beta = -b/a = -1/6

alpa(beta) = c/a = -2/6 = -1/3

To find : alpa /beta + beta/alpa

= a/b + b/a

= b + a/ab

= -1/6/-1/3

= -1/6 (3/-1)

= -3/-6

= 1/2

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Answer 2

Answer:

f(x)=6x²+x-2

let alpha be m and bitta be n.( u let on your choice or not)

then, m+n= -b/a =-1/6

mn=c/a= -2/6

now,

m/n+n/m =m²+n²/mn

=(m+n)²-2mn /(-2/6)

={(-1/6)²-2×-2/6} /(-1/3)

=(1/36+2/3) /(-1/3)

=(25/36) /(-1/3)

=-25/12 Ans

hope it will help u!!!!

thank u