Math, asked by bittutiwari465, 1 year ago

Find the area of atriangular region whose base is 90m long and the corresponding altitude is 40m long.

Answers

Answered by abhi569
2
I hope this will help you

Area of triangle =height*length/2
area =90*40/2
Area =90*20
Area =1800m²
Answered by Rahul999
1
1/2*90*40=1800 sq m
 \frac{1}{2}  \times 90 \times 40 =
1800 sq m
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