Question

find the area of AYB radius of circle21cm angle O 120

Answer 1

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Answer 2

here is the solution

Area of AYB = r^2(πQ÷360 - sinQ÷2)
= 21×21(3.14×120÷360 - 0.86÷2 )
= 441 ( 376.8÷360 - 0.43 )
= 441 ( 1.046 - 0.43 )
= 441 × 0.616
= 271.6 56 sq.cm.