Question

Find the area of board of coordinates A(2,2) B (8,2) C(8,6) D (2,6)

Answer 1

Answer:

it is a rectangle with sides 4 and 6

thus, area=6×4=24unit^2

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Answer 2

The area of board of coordinates A(2,2) B (8,2) C(8,6) D (2,6) is 24 square units .

Explanation:

Given  : The coordinates of the board = A(2,2) B (8,2) C(8,6) D (2,6)

Length : Distance between AB = |8-2|= 6 units  [only x-coordinate is changed from A to B]

Width : Distance between AD = |6-2|= 4 units [only y-coordinate is changed from A to D]

Now , Area of the board = Length x Width

= 6 x 4 square units

= 24 square units

Therefore , the area of board of coordinates A(2,2) B (8,2) C(8,6) D (2,6) is 24 square units .

# Learn more :

The sum of x-coordinates of the vertices of the triangle is 18 and that of y-coordinates is 24 then the coordinates of its centroid are..............

(a) (6,8)

(b) (8,6)

(c) (9,12)

(d) (12,9)​

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