Find the area of enclosed by each of the following figure
Answers
Answer:
741 cm²
(i) Step-by-step explanation:
B = Square = 24 cm × 24 cm
= 576 cm²
A = Trapizoid = 1/2 × (9 cm + 24 cm) × 10 cm²
= 165 cm²
So, the total area: (576 cm² + 165 cm²)
= 741 cm²
(ANS)
(ii) Step-by-step explanation:
B = Square = 24 cm × 24 cm
= 576 cm²
Let's suppose the figure A as a rectangle:
A = rectangle = 10 cm × 24 cm
= 240 cm²
So, The total area is = 576 cm² + 240 cm²
= 816 cm²
But, as it's not a rectangle. So, we have to subtract the 2 triangles...
Here, 24 cm - 9 cm
= 15 cm
It's on the total for both sides.
So, 15 cm/ 2
= 7.5 cm
Now, the area = triangle = 1/2 × 7.5 cm × 10 cm
= 37.5 cm²
As, there are 2 triangles,
2 × 37.5 cm²
= 75 cm²
Now, we need to subtract it,
816 cm² - 75 cm²
= 714 cm²
(ANS)
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