find the area of equalatral triangle's of side 8cm
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AREA=1/2BH
TO FIND THE HEIGHT WE HAVE A RIGHT TRIANGLE WITH THE HYPOTENUSE=8 & ONE SIDE=4
8^2=4^2+X^2 WHERE X IS THE HEIGHT.
64=16+X^2
X^2=64-16
X^2=48
X=SQRT48
X=6.928 FOR THE HEIGHT.
AREA=1/2*8*6.928
AREA=27.71 ANSWER.PLEASE MARK AS BRAINLIEST
TO FIND THE HEIGHT WE HAVE A RIGHT TRIANGLE WITH THE HYPOTENUSE=8 & ONE SIDE=4
8^2=4^2+X^2 WHERE X IS THE HEIGHT.
64=16+X^2
X^2=64-16
X^2=48
X=SQRT48
X=6.928 FOR THE HEIGHT.
AREA=1/2*8*6.928
AREA=27.71 ANSWER.PLEASE MARK AS BRAINLIEST
Answered by
0
AREA=1/2BH
TO FIND THE HEIGHT WE HAVE A RIGHT TRIANGLE WITH THE HYPOTENUSE=8 & ONE SIDE=4
8^2=4^2+X^2 WHERE X IS THE HEIGHT.
64=16+X^2
X^2=64-16
X^2=48
X=SQRT48
X=6.928 FOR THE HEIGHT.
AREA=1/2*8*6.928
AREA=27.71 ANSWER.
TO FIND THE HEIGHT WE HAVE A RIGHT TRIANGLE WITH THE HYPOTENUSE=8 & ONE SIDE=4
8^2=4^2+X^2 WHERE X IS THE HEIGHT.
64=16+X^2
X^2=64-16
X^2=48
X=SQRT48
X=6.928 FOR THE HEIGHT.
AREA=1/2*8*6.928
AREA=27.71 ANSWER.
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