Find the area of equilateral triangle whose altitude is 16V3 cm.
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Answer:
Step-by-step explanation:
Length of each side = x
By Pythagoras theorem,
Altitude = √(x^2-(x/2)^2)=√3/2×x
So √3/2×x = 16√3
x = 32
Area = 0.5×base×height
= 0.5×32×16√3 = 256√3cm^2
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