Question

find the area of equilateral triangle whose one side is 14 cm​

Answer 1

Given sides of triangle

a=13,b=14,c=15

Semi-perimeter s=21(a+b+c)=21(13+14+15)=21

Area, A = s(s−a)(s−b)(s−c)

A=21(21−13)(21−14)(21−15)

A=84 cm2

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